Tentukan nilai x dari 64 ^ x + 1 = 4 ^ 2 x + 5
Jawaban:
64^x + 1 = 4^2x + 5
(2^6)^x + 1 = (2^2)^2x + 5
6x + 6 = 4x + 10
2x = 4
x = 2
[answer.2.content]Jawaban:
64^x + 1 = 4^2x + 5
(2^6)^x + 1 = (2^2)^2x + 5
6x + 6 = 4x + 10
2x = 4
x = 2
[answer.2.content]